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प्रश्न
Find the approximate value of cos (60° 30').
(Given: 1° = 0.0175c, sin 60° = 0.8660)
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उत्तर
Let `f(X)=cosx`
`f'(x)=-sinx`
`x=60^@30'=60^@+(1/2)^@=a+h`
Here, `a=60^@=pi/3`
and `h=(1/2)^@=(0.0175)/2=0.00875`
`f(a)=f(pi/3)=cos(pi/3)=1/2=0.5`
`f'(a)=f'(pi/3)=-sin(pi/3)=-0.8660`
`f(a+h)~~f(a)+hf'(a)`
`cos(60^@30')~~0.5+(0.00875)(-0.8660)`
`~~0.5-0.0075775`
`~~0.4924`
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