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Find the approximate values of : sin 61° , given that 1° = 0.0174c, 3=1.732 - Mathematics and Statistics

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प्रश्न

Find the approximate values of : sin 61° , given that 1° = 0.0174c, `sqrt(3) = 1.732`

योग
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उत्तर

Let f(x) = sin x

Then f'(x) = `d/dx(sin x) = cos x`

Take a = 60° = `pi/(3) and h = 1°` = 0.0174c

Then f(a) = `f(pi/3)`

= `sin  pi/(3)`

= `sqrt(3)/(2)`

= `(1.732)/(2)`

= 0.866
and
f'(a) = `f'(pi/3)`

= `cos  pi/(3)`

= `(1)/(2)`
= 0.5
The formula for approximation is
f(a + h) ≑ f(a) + h.f'(a)

∴ sin 61° = f(61°)

= `f(pi/3 + 0.0174)`

≑ `f(pi/3) + 0.0174.f'(pi/3)`

≑ 0.866 + 0.0174 x 0.5
≑ 0.866 + 0.00870
= 0.8747
∴ sin 61° ≑ 0.8747.

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अध्याय 2: Applications of Derivatives - Exercise 2.2 [पृष्ठ ७५]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 2 Applications of Derivatives
Exercise 2.2 | Q 2.1 | पृष्ठ ७५

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