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Find the approximate values of : e0.995, given that e = 2.7183.

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प्रश्न

Find the approximate values of : e0.995, given that e = 2.7183.

योग
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उत्तर

Let f(x) = ex.

Then f'(x) = `d/dx(e^x) = e^x`

Take a = 1 and h = – 0.005.
Then f(a) = f(1) = e = 2.7183
and f'(a) = f'(1) = e = 2.7183
The formula for approximation is
f(a + h) ≑ f(a) + h.f'(a)
∴ e.0995 = f(0.995)
= f(1 – 0.005)
≑ f(1) – (0.005).f'(1)
≑ 2.7183 – 0.005 x 2.7183
≑ 2.7183 – 0.01359
= 2.70471
∴ e0.995 ≑ 2.70471.

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अध्याय 2: Applications of Derivatives - Exercise 2.2 [पृष्ठ ७५]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 2 Applications of Derivatives
Exercise 2.2 | Q 4.1 | पृष्ठ ७५

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