हिंदी

Using Differentials, Find the Approximate Value of Each of the Following. `(17/81)^(1/4)` - Mathematics

Advertisements
Advertisements

प्रश्न

Using differentials, find the approximate value of each of the following.

`(17/81)^(1/4)`

 

Advertisements

उत्तर

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Application of Derivatives - Exercise 6.6 [पृष्ठ २४२]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 6 Application of Derivatives
Exercise 6.6 | Q 1.1 | पृष्ठ २४२

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Using differentials, find the approximate value of the following up to 3 places of decimal

`(0.999)^(1/10)`


Using differentials, find the approximate value of the following up to 3 places of decimal

`(82)^(1/4)`


Using differentials, find the approximate value of the following up to 3 places of decimal

`(26.57)^(1/3)`


Using differentials, find the approximate value of the following up to 3 places of decimal

`(32.15)^(1/5)`


The approximate change in the volume of a cube of side x metres caused by increasing the side by 3% is

A. 0.06 x3 m3 

B. 0.6 x3 m3

C. 0.09 x3 m3

D. 0.9 x3 m3


Using differentials, find the approximate value of each of the following.

`(33)^(1/5)`


The pressure p and the volume v of a gas are connected by the relation pv1.4 = const. Find the percentage error in p corresponding to a decrease of 1/2% in v .


1 Using differential, find the approximate value of the following:

\[\sqrt{25 . 02}\]


Using differential, find the approximate value of the following:  \[\left( 0 . 009 \right)^\frac{1}{3}\]


Using differential, find the approximate value of the following: \[\left( 0 . 007 \right)^\frac{1}{3}\]


Using differential, find the approximate value of the \[\sqrt{401}\] ?


Using differential, find the approximate value of the \[\left( 15 \right)^\frac{1}{4}\] ?


Using differential, find the approximate value of the \[\frac{1}{(2 . 002 )^2}\] ?


Using differential, find the approximate value of the loge 4.04, it being given that log104 = 0.6021 and log10e = 0.4343 ?


Using differential, find the approximate value of the loge 10.02, it being given that loge10 = 2.3026 ?


Using differential, find the approximate value of the \[\cos\left( \frac{11\pi}{36} \right)\] ?


Using differential, find the approximate value of the \[\left( \frac{17}{81} \right)^\frac{1}{4}\] ?


Using differential, find the approximate value of the \[{25}^\frac{1}{3}\] ?


Find the approximate value of f (2.01), where f (x) = 4x2 + 5x + 2 ?


Find the approximate value of log10 1005, given that log10 e = 0.4343 ?


Find the approximate change in the surface area of a cube of side x metres caused by decreasing the side by 1% ?


If the percentage error in the radius of a sphere is α, find the percentage error in its volume ?


If there is an error of 2% in measuring the length of a simple pendulum, then percentage error in its period is


A sphere of radius 100 mm shrinks to radius 98 mm, then the approximate decrease in its volume is


The circumference of a circle is measured as 28 cm with an error of 0.01 cm. The percentage error in the area is

 


Find the approximate values of : `sqrt(8.95)`


Find the approximate values of : `root(5)(31.98)`


Find the approximate values of sin (29° 30'), given that 1° = 0.0175°, `sqrt(3) = 1.732`.


Find the approximate values of : cos(60° 30°), given that 1° = 0.0175°, `sqrt(3) = 1.732`


Find the approximate values of : loge(9.01), given that log 3 = 1.0986.


The approximate value of the function f(x) = x3 − 3x + 5 at x = 1.99 is ____________.


Find the approximate value of (1.999)5.


If y = x4 – 10 and if x changes from 2 to 1.99, what is the change in y ______.


If the radius of a sphere is measured as 9 cm with an error of 0.03 cm, then find the approximating error in calculating its volume.


Find the approximate value of f(3.02), where f(x) = 3x2 + 5x + 3


The approximate change in volume of a cube of side `x` meters coverd by increasing the side by 3% is


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×