Advertisements
Advertisements
प्रश्न
(i) A 200g ball is thrown vertically upward with an initial velocity of 30 ms-1. Draw a velocity-time graph for the motion of ball.
(ii) How long will the ball take to reach the highest point?
(iii) What will be the kinetic energy of ball, when it returns to the starting point, neglecting the air resistance?
(iv) What will be the potential energy of ball at highest point?
Advertisements
उत्तर
Given : m = 0.200 kg; v = 30 ms−1
(i) Shown in diagram alongside.
(ii) 3 seconds.
(iii) K.E. = `1/2` mv2 = `1/2xx(30)^2` = 90 J.
(iv) P.E. = K.E. = 90 J.
[By the law of conservation of energy]
संबंधित प्रश्न
Why is a jack screw provided with a long arm?
Power spent by a body depends on the time for which it does work.
When does a force perform work?
1 J = ______ calorie.
A bullet of mass 0.5 kg slows down from a speed of 5 m s-1 to that of 3 m s-1. Calculate the change in kinetic energy of the ball.
The work done on an object does not depend on the :
Ravi applied a force of 10 N and moved a book 30 cm in the direction of the force. How much was the work done by Ravi?
What are the advantages and disadvantages of using solar cells for producing electricity?
Calculate the work done when:
A 5 kg weight is lifted 10 m vertically. (g = 9.8 m/s2)
A ______ should act on an object.
