हिंदी

How would the stopping potential for a given photosensitive surface change if the frequency of the incident radiation were increased? Justify your answer.

Advertisements
Advertisements

प्रश्न

How would the stopping potential for a given photosensitive surface change if the frequency of the incident radiation were increased? Justify your answer.

टिप्पणी लिखिए
Advertisements

उत्तर

The stopping potential for a certain photosensitive surface increases as the frequency of the incident radiation increases. This is because the stopping potential is directly proportional to the frequency of the incident radiation, according to the photoelectric effect equation: Kmax = hf - Φ, where h is Planck's constant, f is the frequency of incident radiation and the metal's work function. Kmax is the photoelectron's maximal kinetic energy. As a result, as the frequency of the input radiation increases, so does the stopping potential required to stop the photoelectrons, while the kinetic energy of the photoelectrons emitted decreases.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2022-2023 (March) Delhi Set 1

संबंधित प्रश्न

(a) Estimate the speed with which electrons emitted from a heated emitter of an evacuated tube impinge on the collector maintained at a potential difference of 500 V with respect to the emitter. Ignore the small initial speeds of the electrons. The specific charge of the electron, i.e., its e/m is given to be 1.76 × 1011 C kg−1.

(b) Use the same formula you employ in (a) to obtain electron speed for an collector potential of 10 MV. Do you see what is wrong? In what way is the formula to be modified?


What is the speed of a photon with respect to another photon if (a) the two photons are going in the same direction and (b) they are going in opposite directions?


Can a photon be deflected by an electric field? Or by a magnetic field?


Light of wavelength λ falls on a metal with work-function hc/λ0. Photoelectric effect will take place only if


A photon of energy hv is absorbed by a free electron of a metal with work-function hv − φ.


A totally reflecting, small plane mirror placed horizontally faces a parallel beam of light, as shown in the figure. The mass of the mirror is 20 g. Assume that there is no absorption in the lens and that 30% of the light emitted by the source goes through the lens. Find the power of the source needed to support the weight of the mirror.

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


The electric field associated with a monochromatic beam is 1.2 × 1015 times per second. Find the maximum kinetic energy of the photoelectrons when this light falls on a metal surface whose work function is 2.0 eV.

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


Define the term: stopping potential in the photoelectric effect.


If photons of ultraviolet light of energy 12 eV are incident on a metal surface of work function of 4 eV, then the stopping potential (in eV) will be :


The difference between threshold wavelengths for two metal surfaces A and B having work function ΦA = 9 eV and  ΦB = 4.5 eV in nm is ______.

(Given, hc = 1242 eV nm)


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×