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प्रश्न
How the following conversion can be carried out?
2-Methyl-1-propene to 2-chloro-2-methylpropane
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उत्तर
\[\begin{array}{cc}
\phantom{...}\ce{CH3}\phantom{............................}\ce{CH3}\phantom{}\\
|\phantom{................................}|\\
\ce{\underset{2-Methyl-1-propene}{CH3 - C = CH2} ->[HCl][Markovnikov's rule] CH3 - C - CH3}\\
\phantom{................................}|\\
\phantom{.................................}\ce{\underset{2-chloro-2-methylpropane}{Cl}}
\end{array}\]
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संबंधित प्रश्न
Among the isomeric alkanes of molecular formula C5H12, identify the one that on photochemical chlorination yields a single monochloride.
A hydrocarbon C5H10 does not react with chlorine in dark but gives a single monochloro compound C5H9Cl in bright sunlight. Identify the hydrocarbon.
Write the equation for the preparation of 1-iodobutane from 1-butanol.
Write the equation for the preparation of 1-iodobutane from 1-chlorobutane.
How will you bring about the following conversion?
Propene to propyne
How will you bring about the following conversion?
Ethanol to ethyl fluoride
Write the structure of the major organic product in the following reaction:
\[\ce{CH3CH2CH2Cl + NaI ->[acetone][heat]}\]
Write the structure of the major organic product in the following reaction:
\[\ce{CH3CH2CH = CH2 + HBr->[peroxide]}\]
Write the structure of the major organic product in the following reaction:
\[\ce{CH3CH = C(CH3)2 + HBr ->}\]
How the following conversion can be carried out?
Benzyl alcohol to 2-phenylethanoic acid
How the following conversion can be carried out?
But-1-ene to n-butyliodide
Which is the incorrect option?
Alkyl halides are prepared from alcohols by treating with ______.
The reagent used in the conversion of 1-butanol to 1-bromobutane is ______.
Predict the major product ‘P’ in the following sequence of reactions:

How many products (including stereoisomers) are expected from the monochlorination of the following compound?
\[\begin{array}{cc}
\ce{H3C}\phantom{..................................}\\
\backslash\phantom{...........................}\\
\ce{CH - CH2 - CH3}\\
/\phantom{...........................}\\
\ce{H3C}\phantom{...................................}
\end{array}\]
