Advertisements
Advertisements
प्रश्न
Given that HCF (306, 657) = 9, find LCM (306, 657).
Advertisements
उत्तर
By the property that LCM × HCF = Product of the two numbers
LCM × 9 = 306 × 657
LCM = `(306 xx 657)/9`
= 34 × 657
= 22338
Therefore, LCM of 306 and 657 is 22338.
संबंधित प्रश्न
Express the number as a product of its prime factor:
140
Explain why 7 × 11 × 13 + 13 and 7 × 6 × 5 × 4 × 3 × 2 × 1 + 5 are composite numbers.
There is a circular path around a sports field. Sonia takes 18 minutes to drive one round of the field, while Ravi takes 12 minutes for the same. Suppose they both start at the same point and at the same time, and go in the same direction. After how many minutes will they meet again at the starting point?
State fundamental theorem of arithmetic?
Find the LCM and HCF of the following pair of integers and verify that LCM × HCF = Product of the two numbers.
26 and 91
Can two numbers have 16 as their HCF and 380 as their LCM? Give reason.
Write down the decimal expansions of the following rational numbers by writing their denominators in the form 2m × 5n, where, m, n are non-negative integers.\[\frac{13}{125}\]
If the prime factorization of a natural number n is 23 ✕ 32 ✕ 52 ✕ 7, write the number of consecutive zeros in n.
LCM of the given number ‘x’ and ‘y’ where y is a multiple of ‘x’ is given by ______.
The ratio of LCM and HCF of the least composite and the least prime numbers is ______.
For some integer q, every odd integer is of the form ______.
n2 – 1 is divisible by 8, if n is ______.
The largest number which divides 70 and 125, leaving remainders 5 and 8, respectively, is ______.
The least number that is divisible by all the numbers from 1 to 10 (both inclusive) is ______.
Can two numbers have 18 as their HCF and 380 as their LCM? Give reasons.
Show that 12n cannot end with the digit 0 or 5 for any natural number n.
Show the 6n cannot end with digit 0 for any natural number 'n'.
Assertion (A): The HCF of two numbers is 5 and their product is 150. Then their LCM is 40.
Reason(R): For any two positive integers a and b, HCF (a, b) × LCM (a, b) = a × b.
If n is a natural number, then 8n cannot end with digit
If two positive integers a and b are written as a = x3y2 and b = xy3, where x, y are prime numbers, then the result obtained by dividing the product of the positive integers by the LCM (a, b) is ______.
