हिंदी

Given that HCF (306, 657) = 9, find LCM (306, 657).

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प्रश्न

Given that HCF (306, 657) = 9, find LCM (306, 657).

योग
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उत्तर

By the property that LCM × HCF = Product of the two numbers

LCM ×  9 = 306 × 657

LCM = `(306 xx 657)/9`

= 34 × 657

 = 22338

Therefore, LCM of 306 and 657 is 22338.

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अध्याय 1: Real Numbers - EXERCISE 1.1 [पृष्ठ ५]

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एनसीईआरटी Mathematics [English] Class 10
अध्याय 1 Real Numbers
EXERCISE 1.1 | Q 4. | पृष्ठ ५
आर.डी. शर्मा Mathematics [English] Class 10
अध्याय 1 Real Numbers
Exercise 1.4 | Q 3 | पृष्ठ ३९

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