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Find the LCM and HCF of the following pair of integers and verify that LCM × HCF = product of the two numbers. 510 and 92 - Mathematics

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प्रश्न

Find the LCM and HCF of the following pair of integers and verify that LCM × HCF = product of the two numbers.

510 and 92

योग
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उत्तर

510 = 2 × 3 × 5 × 17

92 = 2 × 2 × 23

Therefore, 510 = 2 × 3 × 5 × 17   ...(A)

92 = 2 × 46

= 2 × 2 × 23    ...(B)

From (A) and (B) HCF of 510 and 92 is = 2 and their 

LCM is 2 × 2 × 3 × 5 × 17 × 23 = 23460

Product of the LCM and HCF = 2 × 23460 = 46920

Product of the two numbers = 510 × 92 = 46920

Therefore, it is proved that LCM × HCF = Product of the two numbers.

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अध्याय 1: Real Numbers - Exercise 1.4 [पृष्ठ ३९]

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आरडी शर्मा Mathematics [English] Class 10
अध्याय 1 Real Numbers
Exercise 1.4 | Q 1.2 | पृष्ठ ३९
एनसीईआरटी Mathematics [English] Class 10
अध्याय 1 Real Numbers
EXERCISE 1.1 | Q 2. (ii) | पृष्ठ ५

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