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प्रश्न
Give one chemical test to distinguish between the following pair of compounds.
Aniline and benzylamine
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उत्तर
Aniline and benzylamine can be distinguished by their reactions with the help of nitrous acid, which is prepared in situ from a mineral acid and sodium nitrite. Benzylamine reacts with nitrous acid to form unstable diazonium salt, which in turn gives alcohol with the evolution of nitrogen gas.
\[\ce{\underset{Benzylamine}{C6H5CH2 - NH2} + HNO2 ->[NaNO2 + HCl] \underset{(Unstable)}{[C6H5CH2 - \overset{+}{N2}C\overset{-}{l}]} ->[H2O] N2 ^ + \underset{Benzy alcohol}{C6H5CH2 - OH} + HCl}\]
On the other hand, aniline reacts with HNO2 at a low temperature to form stable diazonium salt. Thus, nitrogen gas is not evolved.
\[\ce{C6H5NH2 ->[NaNO2 + HCl][273 - 278 K] C6H5 - \overset{+}{N2}C\overset{-}{l} + NaCl + 2H2O}\]
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संबंधित प्रश्न
Which among the following molecular formulae represents urotropine?
(a) C6H12N4
(b) C6H24H4
(c) C6H12N4O2
(d) C6H24N4O2
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C6H5NHCH3
Write the IUPAC name of the following compound and classify it as primary, secondary and tertiary amine.
(CH3CH2)2NCH3
Give one chemical test to distinguish between the following pair of compounds.
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\[\ce{C6H5NH2 + H2SO4 (conc.)}\]
Complete the following reaction:
\[\ce{C6H5N2Cl + C2H5OH ->}\]
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An organic compound (A) with molecular formula C3H7NO on heating with Br2 and KOH forms a compound (B). Compound (B) on heating with CHCl3 and alcoholic KOH produces a foul-smelling compound (C) and on reacting with C6H5SO2Cl forms a compound (D) which is soluble in alkali. Write the structure of (A), (B), (C) and (D).
Do the following conversions in not more than two steps:
