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प्रश्न
An organic compound (A) with molecular formula C3H7NO on heating with Br2 and KOH forms a compound (B). Compound (B) on heating with CHCl3 and alcoholic KOH produces a foul-smelling compound (C) and on reacting with C6H5SO2Cl forms a compound (D) which is soluble in alkali. Write the structure of (A), (B), (C) and (D).
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उत्तर
\[\ce{CH3\underset{(A)}{CH2}CONH2 + Br2 + KOH -> CH3\underset{(B)}{CH2}NH2}\]
\[\ce{CH3\underset{(B)}{CH2}NH2 + CHCl3 + KOH -> CH3\underset{(C)}{CH2}NC + KCl + H2O}\]

A = Propanaimde
B = Ethyl amine (1° amine)
C = Ethyl isocyanide
D = N-ethyl benzene sulphonamide
APPEARS IN
संबंधित प्रश्न
Account for the following:
pKb of aniline is more than that of methylamine.
Account for the following:
Ethylamine is soluble in water, whereas aniline is not.
How will you convert ethanoic acid into methanamine?
How will you convert methanamine into ethanamine?
How will you convert propanoic acid into ethanoic acid?
Accomplish the following conversion:
Aniline to benzyl alcohol
Complete the following reaction:
\[\ce{C6H5N2Cl + C2H5OH ->}\]
Do the following conversions in not more than two steps :
Propanone to Propene
Using IUPAC norms, write the formula of Hexaamminecobalt(III) sulphate.
Do the following conversions in not more than two steps:
\[\begin{array}{cc}
\ce{CH3CN to CH3 - C - CH3}\\
\phantom{...........}||\\
\phantom{...........}\ce{O}
\end{array}\]
