Advertisements
Advertisements
प्रश्न
Forty percent of business travellers carry a laptop. In a sample of 15 business travelers, what is the probability that 3 will have a laptop?
Advertisements
उत्तर
Given n = 5
p = `40/10 = 2/5`
q = 1 – p = `1 - 2/5 = (5-2)/5 = 3/5`
The binomial distribution P(X = x) = `15"c"_x (2/5)^x (3/5)^(15 - x)`
P(probability that 3 will have a laptop) = P(X = 3)
= `15"c"_3 (2/5)^3 (/5)^(15 - 3)`
= `(15 xx 14 xx 13)/(1 xx 2 xx 3) xx (2)^3/(5)^3 xx (3)^12/(5)^12`
= `455 xx (8 xx 5.311 xx 10^5)/(5)^15`
= `(3640 xx 5.311 xx 10^5)/(3.055 xx 10^10)`
= `(3640 xx 5.311)/(3.055 xx 10^5)`
= `19332.04/305500`
= 0.06328
APPEARS IN
संबंधित प्रश्न
If 5% of the items produced turn out to be defective, then find out the probability that out of 20 items selected at random there are exactly three defectives
If the probability of success is 0.09, how many trials are needed to have a probability of atleast one success as 1/3 or more?
Determine the binomial distribution for which the mean is 4 and variance 3. Also find P(X=15)
Define Poisson distribution
Write any 2 examples for Poisson distribution
Define Normal distribution
Choose the correct alternative:
The parameters of the normal distribution f(x) = `(1/sqrt(72pi))"e"^(-(x - 10)^2)/72 - oo < x < oo`
Choose the correct alternative:
A manufacturer produces switches and experiences that 2 percent switches are defective. The probability that in a box of 50 switches, there are atmost two defective is :
Choose the correct alternative:
The random variable X is normally distributed with a mean of 70 and a standard deviation of 10. What is the probability that X is between 72 and 84?
The annual salaries of employees in a large company are approximately normally distributed with a mean of $50,000 and a standard deviation of $20,000. What percent of people earn less than $40,000?
