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The mortality rate for a certain disease is 7 in 1000. What is the probability for just 2 deaths on account of this disease in a group of 400? [Given e–2.8 = 0.06] - Business Mathematics and Statistics

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प्रश्न

The mortality rate for a certain disease is 7 in 1000. What is the probability for just 2 deaths on account of this disease in a group of 400? [Given e–2.8 = 0.06]

योग
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उत्तर

Since the mortality rate for a certain disease in 7 in loop

∴ p = `7/1000` and n = 400

The value of mean A = λp

= `400 xx 7/1000`

∴ λ = 2.8

Let x be a random variable following distribution with p(x) = `("e"^(-lambda)lambda^x)/(x!)`

∴ The distribution is P(X = 2) = `("e"^(-2 - 8) (2.8)^2)/(2!)`

= `(0.06 xx 7.84)/2`

= 0.2352

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Probability Distributions - Exercise 7.2 [पृष्ठ १५९]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
अध्याय 7 Probability Distributions
Exercise 7.2 | Q 6 | पृष्ठ १५९

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