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If 5% of the items produced turn out to be defective, then find out the probability that out of 20 items selected at random there are find the mean and variance

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प्रश्न

If 5% of the items produced turn out to be defective, then find out the probability that out of 20 items selected at random there are find the mean and variance

योग
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उत्तर

Probability of getting a defective item

p = `5/100 = 1/20`

q = 1 – p

⇒ q = `1 - 1/20`

= `(20 - 1)/20`

q = `19/20` and n = 10

In binomial distribution

P(X = x) = nCxpxqn-x 

Here (X = x)= `10"C"_x (1/20)^x (19/20)(10 - x)`

Mean E(x) = np

= `10 xx 1/20`

= `1/2`

= 0.5

Varaince = npq

= `10 xx 1/20`

= `19/20`

= `19/40`

= 0.475

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Probability Distributions - Exercise 7.1 [पृष्ठ १५५]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
अध्याय 7 Probability Distributions
Exercise 7.1 | Q 6. (iv) | पृष्ठ १५५
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