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Hospital records show that of patients suffering from a certain disease 75% die of it. What is the probability that of 6 randomly selected patients, 4 will recover?

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प्रश्न

Hospital records show that of patients suffering from a certain disease 75% die of it. What is the probability that of 6 randomly selected patients, 4 will recover?

योग
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उत्तर

Let x be the random variable of patience suffering from a certain disease

In a binomial distribution

P(X = x) = ncxpxqn-x 

P(X = 4) = `""^6"C"_4 (1/4)^4 (3/4)^(6 - 4)`

= `""^6"C"_2 (1/4)^4 (3/4)^2`

= `(6 xx 5)/(1 xx 2) [9/(4)^6]`

= `15 xx [9/40946]`

= `135/4096`

= 0.03295

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Probability Distributions - Miscellaneous problems [पृष्ठ १७१]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
अध्याय 7 Probability Distributions
Miscellaneous problems | Q 2 | पृष्ठ १७१

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