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प्रश्न
Fluorine is a stronger oxidising agent than chlorine. Why?
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उत्तर
The oxidising power of halogens decreases as we go down the group. The electrode potential of F2 is +2.87 V, while that of Cl2 is +1.36 V. This means that fluorine can be reduced more easily than chlorine. Therefore, fluorine is the strongest oxidising agent.
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संबंधित प्रश्न
Draw structure of Chlorine pentafluoride
Account for the following: Fluorine does not exhibit positive oxidation state.
Compare the oxidizing action of F2 and Cl2 by considering parameters such as bond dissociation enthalpy, electron gain enthalpy and hydration enthalpy.
F2 has lower bond dissociation enthalpy than Cl2. Why?
Which halogen compound in the following pair will react faster in SN2 reaction CH3Br or CH3I.
Give two examples to show the anomalous behaviour of fluorine.
Which of the following pairs of ions are isoelectronic and isostructural?
Reduction potentials of some ions are given below. Arrange them in decreasing order of oxidising power.
| Ion | \[\ce{CIO^{-}_{4}}\] | \[\ce{IO^{-}_{4}}\] | \[\ce{BrO^{-}_{4}}\] |
| Reduction potential EΘ/V |
EΘ = 1.19 V | EΘ = 1.65V | EΘ = 1.74 V |
Solubility of iodine in water may be increase by adding
Statement I: Acid strength increases in the order given as HF << HCl << HBr << HI.
Statement II: As the size of the elements F, Cl, Br, and I increase down the group, the bond strength of HF, HCl, HBr and HI decreases and so the acid strength increases.
In the light of the above statements, choose the correct answer from the options given below.
