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प्रश्न
Fluorine is a stronger oxidising agent than chlorine. Why?
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उत्तर
The oxidising power of halogens decreases as we go down the group. The electrode potential of F2 is +2.87 V, while that of Cl2 is +1.36 V. This means that fluorine can be reduced more easily than chlorine. Therefore, fluorine is the strongest oxidising agent.
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संबंधित प्रश्न
Draw structure of Chlorine pentafluoride
Account for the following :
Acidic character increases from HF to HI.
Arrange the following in the order of property indicated for the given set:
HF, HCl, HBr, HI - increasing acid strength.
Cl2 acts as a bleaching agent.
Which one has the lowest boiling point?
Which of the following pairs of ions are isoelectronic and isostructural?
Reduction potentials of some ions are given below. Arrange them in decreasing order of oxidising power.
| Ion | \[\ce{CIO^{-}_{4}}\] | \[\ce{IO^{-}_{4}}\] | \[\ce{BrO^{-}_{4}}\] |
| Reduction potential EΘ/V |
EΘ = 1.19 V | EΘ = 1.65V | EΘ = 1.74 V |
Which of the following statements are true?
(i) Only type of interactions between particles of noble gases are due to weak dispersion forces.
(ii) Ionisation enthalpy of molecular oxygen is very close to that of xenon.
(iii) Hydrolysis of XeF6 is a redox reaction.
(iv) Xenon fluorides are not reactive.
Solubility of iodine in water may be increase by adding
The reaction \[\ce{3ClO- (aq) -> ClO3- (aq) + 2Cl- (aq) + 2Cl- (aq)}\] is an example of
