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प्रश्न
Fluorine is a stronger oxidising agent than chlorine. Why?
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उत्तर
The oxidising power of halogens decreases as we go down the group. The electrode potential of F2 is +2.87 V, while that of Cl2 is +1.36 V. This means that fluorine can be reduced more easily than chlorine. Therefore, fluorine is the strongest oxidising agent.
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संबंधित प्रश्न
Account for the following: Fluorine does not exhibit positive oxidation state.
Which halogen compound in the following pair will react faster in SN2 reaction CH3Br or CH3I.
Which halogen compound in each of the following pairs will react faster in SN2 reaction
(CH3)3 C – Cl or CH3 – Cl
Write the reactions of F2 with water.
Complete the following equations:
KMnO4 
Bond dissociation enthalpy of E–H (E = element) bonds is given below. Which of the compounds will act as the strongest reducing agent?
| Compound | \[\ce{NH3}\] | \[\ce{PH3}\] | \[\ce{AsH3}\] | \[\ce{SbH3}\] |
| Δdiss (E – H)/kJ mol–1 | 389 | 322 | 297 | 255 |
Which of the following statements are true?
(i) Only type of interactions between particles of noble gases are due to weak dispersion forces.
(ii) Ionisation enthalpy of molecular oxygen is very close to that of xenon.
(iii) Hydrolysis of XeF6 is a redox reaction.
(iv) Xenon fluorides are not reactive.
Iodine has lowest oxidiation state in ______.
Statement I: Acid strength increases in the order given as HF << HCl << HBr << HI.
Statement II: As the size of the elements F, Cl, Br, and I increase down the group, the bond strength of HF, HCl, HBr, and HI decreases and so the acid strength increases.
In the light of the above statements, choose the correct answer from the options given below.
Arrange the following in the increasing order of the property mentioned:
MF, MCl, MBr, MI (ionic character)
