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Five boys and five girls form a line. Find the number of ways of making the seating arrangement under the following condition: C1 C2 (a) Boys and girls alternate: (i) 5! × 6! (b) No two girls sit to - Mathematics

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प्रश्न

Five boys and five girls form a line. Find the number of ways of making the seating arrangement under the following condition:

C1 C2
(a) Boys and girls alternate: (i) 5! × 6!
(b) No two girls sit together : (ii) 10! – 5! 6!
(c) All the girls sit together (iii) (5!)2 + (5!)2
(d) All the girls are never together : (iv) 2! 5! 5!
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उत्तर

C1 C2
(a) Boys and girls alternate: (i) (5!)2 + (5!)2
(b) No two girls sit together : (ii) 5! × 6!
(c) All the girls sit together (iii) 2! 5! 5!
(d) All the girls are never together : (iv) 10! – 5! 6!

Explanation:

(a) Total number of arrangement when boys and girls alternate: = (5!)2 + (5!)2

(b) No two girls sit together: = 5! 6!

(c) All the girls sit together = 2! 5! 5!

(d) All the girls sit never together = 10! – 5! 6!

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अध्याय 7: Permutations and Combinations - Exercise [पृष्ठ १२७]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 7 Permutations and Combinations
Exercise | Q 61 | पृष्ठ १२७

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