Advertisements
Advertisements
प्रश्न
Find x in the following figure:
Advertisements
उत्तर
We know that the sum of all exterior angles of any polygon is 360º.
125° + 125° + x = 360°
250° + x = 360°
x = 360° − 250°
x = 110°
APPEARS IN
संबंधित प्रश्न
Find x + y + z
The angles of a quadrilateral are in the ratio 3 : 5 : 9 : 13 Find all the angles of the quadrilateral.
Two opposite angles of a parallelogram are (3x – 2)° and (50 – x)°. Find the measure of each angle of the parallelogram .
ABCD is a parallelogram in which ∠A = 70°. Compute ∠B, ∠C and ∠D .
In a quadrilateral ABCD, bisectors of angles A and B intersect at O such that ∠AOB = 75°, then write the value of ∠C + ∠D.
If the diagonals of a rhombus are 18 cm and 24 cm respectively, then its side is equal to
In a rhombus ABCD, if ∠ACB = 40°, then ∠ADB =
Can the angles 110º, 80º, 70º and 95º be the angles of a quadrilateral? Why or why not?
Can all the angles of a quadrilateral be acute angles? Give reason for your answer.
In the following figure, P is the mid-point of side BC of a parallelogram ABCD such that ∠BAP = ∠DAP. Prove that AD = 2CD.
