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Find the sum of first 15 multiples of 8. - Mathematics

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प्रश्न

Find the sum of first 15 multiples of 8.

योग
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उत्तर १

The multiples of 8 are

8, 16, 24, 32…

These are in an A.P., having the first term as 8 and common difference as 8.

Therefore, a = 8

d = 8

S15 =?

`S_n = n/2[2a+(n-1)d]`

= `15/2[2(8)+(15-1)8]`

= `15/2[16+14(8)]`

= `15/2(16+112)`

= `(15(128))/2`

= 15 × 64

= 960

Therefore, the sum of the first 15 multiples of 8 is 960.

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उत्तर २

Multiples of 8 are: 8, 16, 24, 32, ........... , Which form an A.P. with first term, a = 8 and common difference, d = 8

∵ Sum of nth term of A.P.

Sn = `n/2[2a + (n - 1)d]`

∴ S15 = `15/2 [2 xx 8 + (15 - 1) xx 8]`

= `15/2 [16 + 112]`

= `15/2 xx 128`

= 15 × 64

= 960

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Arithmetic Progressions - Exercise 5.3 [पृष्ठ ११३]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 10
अध्याय 5 Arithmetic Progressions
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आर.एस. अग्रवाल Mathematics [English] Class 10
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Exercise 5.6 | Q 12.1 | पृष्ठ ५१

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