Advertisements
Advertisements
प्रश्न
Write the nth term of the \[A . P . \frac{1}{m}, \frac{1 + m}{m}, \frac{1 + 2m}{m}, . . . .\]
Advertisements
उत्तर
In the given AP
\[d = \frac{1 + m}{m} - \frac{1}{m} = \frac{1 + m - 1}{m} = 1\]
APPEARS IN
संबंधित प्रश्न
Find the sum of all numbers from 50 to 350 which are divisible by 6. Hence find the 15th term of that A.P.
In an AP given an = 4, d = 2, Sn = −14, find n and a.
Find the sum of first 40 positive integers divisible by 6.
Find the sum to n term of the A.P. 5, 2, −1, −4, −7, ...,
Find the sum of the first 13 terms of the A.P: -6, 0, 6, 12,....
In an A.P., the sum of first n terms is `(3n^2)/2 + 13/2 n`. Find its 25th term.
Find the 8th term from the end of the AP 7, 10, 13, ……, 184.
The sum of the first n terms of an AP is (3n2+6n) . Find the nth term and the 15th term of this AP.
Write an A.P. whose first term is a and common difference is d in the following.
a = –3, d = 0
Find the A.P. whose fourth term is 9 and the sum of its sixth term and thirteenth term is 40.
In an A.P. the first term is 8, nth term is 33 and the sum to first n terms is 123. Find n and d, the common differences.
If the sum of n terms of an A.P. is 3n2 + 5n then which of its terms is 164?
If the first term of an A.P. is 2 and common difference is 4, then the sum of its 40 terms is
If k, 2k − 1 and 2k + 1 are three consecutive terms of an A.P., the value of k is
The term A.P is 8, 10, 12, 14,...., 126 . find A.P.
The given terms are 2k + 1, 3k + 3 and 5k − 1. find AP.
In a Arithmetic Progression (A.P.) the fourth and sixth terms are 8 and 14 respectively. Find that:
(i) first term
(ii) common difference
(iii) sum of the first 20 terms.
Find S10 if a = 6 and d = 3
If the numbers n - 2, 4n - 1 and 5n + 2 are in AP, then the value of n is ______.
Measures of angles of a triangle are in A.P. The measure of smallest angle is five times of common difference. Find the measures of all angles of a triangle. (Assume the measures of angles as a, a + d, a + 2d)
