Advertisements
Advertisements
प्रश्न
Ramkali required Rs 2,500 after 12 weeks to send her daughter to school. She saved Rs 100 in the first week and increased her weekly saving by Rs 20 every week. Find whether she will be able to send her daughter to school after 12 weeks.
What value is generated in the above situation?
Advertisements
उत्तर
Since Ramkali increased her weekly savings uniformly every week by a fixed number, her savings will form an AP.
Let Sn be the sum of savings in all 12 weeks.
`:.S_n=n/2[2a+(n-1)d]` (Here, a is the money saved in the first week and d is the fixed increase in the weekly savings.)
`=>S_n=12/2[2xx100+(12-1)20]`
= Rs 2520
Ramkali required Rs 2,500 after 12 weeks, but she saved Rs 2,520. So, she will be able to send her daughter to school after 12 weeks.
It shows that Ramkali is aware of the importance of girl child education
APPEARS IN
संबंधित प्रश्न
Find the sum of all natural numbers between 250 and 1000 which are exactly divisible by 3
Find the sum of first 22 terms of an A.P. in which d = 22 and a = 149.
Find the sum of all multiples of 7 lying between 300 and 700.
The first term of an A. P. is 5 and the common difference is 4. Complete the following activity and find the sum of the first 12 terms of the A. P.
a = 5, d = 4, s12 = ?
`s_n = n/2 [ square ]`
`s_12 = 12/2 [10 +square]`
`= 6 × square `
` =square`
Show that a1, a2, a3, … form an A.P. where an is defined as an = 3 + 4n. Also find the sum of first 15 terms.
If a = 6 and d = 10, then find S10.
Find the sum of 12 terms of an A.P. whose nth term is given by an = 3n + 4.
An AP consists of 37 terms. The sum of the three middle most terms is 225 and the sum of the last three is 429. Find the AP.
Find the sum of all the 11 terms of an A.P. whose middle most term is 30.
Which term of the Arithmetic Progression (A.P.) 15, 30, 45, 60...... is 300?
Hence find the sum of all the terms of the Arithmetic Progression (A.P.)
