हिंदी
तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान कक्षा १२

Find the non-parametric form of vector equation and cartesian equation of the plane passing through the point (1, − 2, 4) and perpendicular to the plane x + 2y − 3z = 11 and parallel to the line - Mathematics

Advertisements
Advertisements

प्रश्न

Find the non-parametric form of vector equation and cartesian equation of the plane passing through the point (1, − 2, 4) and perpendicular to the plane x + 2y − 3z = 11 and parallel to the line `(x + 7)/3 = (y + 3)/(-1) = z/1`

योग
Advertisements

उत्तर

The required plane passing through the point `vec"a" = vec"i" - 2vec"j" + 4vec"k"` and parallel to the plane `vec"b" = vec"i" + 2vec"j" - 3vec"k"` and parallel to the line `vec"c" = 3vec"i" - vec"j" + vec"k"`

`vec"b" xx vec"c" = |(vec"i", vec"j", vec"k"),(1, 2, -3),(3, -1, 1)|`

= `vec"i"(2 - 3) - vec"j"(1 + 9) + vec"k"(-1 - 6)`

`vec"b" xx vec"c" = -vec"i" - 10vec"j" - 7vec"k"`

Non-parametric form of vector equation

`(vec"r" - vec"a")*(vec"b" xx vec"c")` = 0

`(vec"r" - vec"a")*(-vec"i" - 10vec"j" - 7vec"k")` = 0

`vec"r"*(-vec"i" - 10vec"j" - 7vec"k") = vec"a"*(-vec"i" - 10vec"j" - 7vec"k")`

`vec"r"*(-vec"i" - 10vec"j" - 7vec"k") = (vec"i" - 2vec"j" + 4vec"k")(-vec"i" - 10vec"j" - 7vec"k")`

`vec"r"*(-vec"i" - 10vec"j" - 7vec"k")` = – 1 + 20 – 28

`vec"r"*(-vec"i" - 10vec"j" - 7vec"k")` = – 9

or

`vec"r"*(vec"i" + 10vec"j" + 7vec"k")` = 9

Cartesian equation

`(xvec"i" + yvec"j" + zvec"k")*(vec"i" + 10vec"j" + 7vec"k")` = 9

x + 10y + 7z – 9 = 0

shaalaa.com
Different Forms of Equation of a Plane
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Applications of Vector Algebra - Exercise 6.7 [पृष्ठ २६३]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 6 Applications of Vector Algebra
Exercise 6.7 | Q 4 | पृष्ठ २६३

संबंधित प्रश्न

Find the vector and Cartesian equation of the plane passing through the point with position vector `2hat"i" + 6hat"j" + 3hat"k"` and normal to the vector `hat"i" + 3hat"j" + 5hat"k"`


A plane passes through the point (− 1, 1, 2) and the normal to the plane of magnitude `3sqrt(3)` makes equal acute angles with the coordinate axes. Find the equation of the plane


Find the non-parametric form of vector equation and Cartesian equation of the plane passing through the point (2, 3, 6) and parallel to thestraight lines `(x - 1)/2 = (y + 1)/3 = (x - 3)/1` and `(x + 3)/2 = (y - 3)/(-5) = (z + 1)/(-3)`


Find the parametric form of vector equation, and Cartesian equations of the plane containing the line `vec"r" = (hat"i" - hat"j" + 3hat"k") + "t"(2hat"i" - hat"j" + 4hat"k")` and perpendicular to plane `vec"r"*(hat"i" + 2hat"j" + hat"k")` = 8


Find the parametric vector, non-parametric vector and Cartesian form of the equation of the plane passing through the point (3, 6, – 2), (– 1, – 2, 6) and (6, 4, – 2)


Show that the lines `(x - 2)/1 = (y - 3)/1 = (z - 4)/3` and `(x - 1)/(-3) = (y - 4)/2 = (z - 5)/1` are coplanar. Also, find the plane containing these lines


Choose the correct alternative:

If `vec"a", vec"b", vec"c"` are three non-coplanar vectors such that `vec"a" xx (vec"b" xx vec"c") = (vec"b" + vec"c")/sqrt(2)` then the angle between `vec"a"` and `vec"b"` is


Choose the correct alternative:

If the line `(x  - )/3 = (y - 1)/(-5) = (x + 2)/2` lies in the plane x + 3y – αz + ß = 0 then (α + ß) is


Choose the correct alternative:

The angle between the line `vec"r" = (hat"i" + 2hat"j" - 3hat"k") + "t"(2hat"i" + hat"j" - 2hat"k")` and the plane `vec"r"(hat"i" + hat"j") + 4` = 0 is


Choose the correct alternative:

Distance from the origin to the plane 3x – 6y + 2z + 7 = 0 is


Choose the correct alternative:

The distance between the planes x + 2y + 3z + 7 = 0 and 2x + 4y + 6z + 7 = 0 is


Choose the correct alternative:

If the distance of the point (1, 1, 1) from the origin is half of its distance from the plane x + y + z + k = 0, then the values of k are


Choose the correct alternative:

If the planes `vec"r"(2hat"i" - lambdahat"j" + hatk")` =  and `vec"r"(4hat"i" + hat"j" - muhat"k")` = 5 are parallel, then the value of λ and µ are


Let d be the distance between the foot of perpendiculars of the points P(1, 2, –1) and Q(2, –1, 3) on the plane –x + y + z = 1. Then d2 is equal to ______.


A plane P contains the line x + 2y + 3z + 1 = 0 = x – y – z – 6, and is perpendicular to the plane –2x + y + z + 8 = 0. Then which of the following points lies on P?


The point in which the join of (–9, 4, 5) and (11, 0, –1) is met by the perpendicular from the origin is ______.


Let (λ, 2, 1) be a point on the plane which passes through the point (4, –2, 2). If the plane is perpendicular to the line joining the points (–2, –21, 29) and (–1, –16, 23), then `(λ/11)^2 - (4λ)/11 - 4` is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×