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Find the parametric form of vector equation, and Cartesian equations of the plane containing the line rijktijkr→=(i^-j^+3k^)+t(2i^-j^+4k^) and perpendicular to plane rijkr→⋅(i^+2j^+k^) = 8 - Mathematics

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प्रश्न

Find the parametric form of vector equation, and Cartesian equations of the plane containing the line `vec"r" = (hat"i" - hat"j" + 3hat"k") + "t"(2hat"i" - hat"j" + 4hat"k")` and perpendicular to plane `vec"r"*(hat"i" + 2hat"j" + hat"k")` = 8

योग
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उत्तर

`vec"a" = hat"i" - hat"j" + 3hat"k"`

`vec"b" = 2hat"i" - hat"j" + 4hat"k"`

`vec"c" = hat"i" + 2hat"j" + hat"k"`

Parametric form of vector equation

`vec"r" = vec"a" + "s"vec"b" + "t"vec"c"`

`vec"r" = (hat"i" - hat"j" + 3hat"k") + "s"(2hat"j" - hat"i" + 4hat"k") + "t"(hat"i" + 2hat"j" + hat"k")`

`vec"b" xx vec"c" = |(hat"i", hat"j", hat"k"),(2, -1, 4),(1, 2, 1)|`

= `hat"i"(- 1 - 8) - hat"j"(2 - 4) + hat"k"(4 + 1)`

= `9hat"i" + 2hat"j" + 5hat"k"`

= `-(9hat"i" - 2hat"j" - 5hat"k")`

Non-parametric form of vector equation:

`(vec"r" - vec"a")*(vec"b" xx vec"c") = vec0`

`[vec"r" - (hat"i" - hat"j" + 3hat"k")]*(-(9hat"i" - 2hat"j" - 5hat"k")) = vec0`

`vec"r"*(+9hat"i" - 2hat"j" - 5hat"k")` = + 9 + 2 – 15

`[vec"r"*(9hat"i" - 2hat"j" - 5hat"k")]` = – 4

Cartesian equation

9x – 2y – 5z = – 4

9x – 2y – 5z + 4 = 0

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Different Forms of Equation of a Plane
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Applications of Vector Algebra - Exercise 6.7 [पृष्ठ २६३]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 6 Applications of Vector Algebra
Exercise 6.7 | Q 5 | पृष्ठ २६३

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