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Find the non-parametric form of vector equation and cartesian equation of the plane passing through the point (1, − 2, 4) and perpendicular to the plane x + 2y − 3z = 11 and parallel to the line - Mathematics

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प्रश्न

Find the non-parametric form of vector equation and cartesian equation of the plane passing through the point (1, − 2, 4) and perpendicular to the plane x + 2y − 3z = 11 and parallel to the line `(x + 7)/3 = (y + 3)/(-1) = z/1`

बेरीज
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उत्तर

The required plane passing through the point `vec"a" = vec"i" - 2vec"j" + 4vec"k"` and parallel to the plane `vec"b" = vec"i" + 2vec"j" - 3vec"k"` and parallel to the line `vec"c" = 3vec"i" - vec"j" + vec"k"`

`vec"b" xx vec"c" = |(vec"i", vec"j", vec"k"),(1, 2, -3),(3, -1, 1)|`

= `vec"i"(2 - 3) - vec"j"(1 + 9) + vec"k"(-1 - 6)`

`vec"b" xx vec"c" = -vec"i" - 10vec"j" - 7vec"k"`

Non-parametric form of vector equation

`(vec"r" - vec"a")*(vec"b" xx vec"c")` = 0

`(vec"r" - vec"a")*(-vec"i" - 10vec"j" - 7vec"k")` = 0

`vec"r"*(-vec"i" - 10vec"j" - 7vec"k") = vec"a"*(-vec"i" - 10vec"j" - 7vec"k")`

`vec"r"*(-vec"i" - 10vec"j" - 7vec"k") = (vec"i" - 2vec"j" + 4vec"k")(-vec"i" - 10vec"j" - 7vec"k")`

`vec"r"*(-vec"i" - 10vec"j" - 7vec"k")` = – 1 + 20 – 28

`vec"r"*(-vec"i" - 10vec"j" - 7vec"k")` = – 9

or

`vec"r"*(vec"i" + 10vec"j" + 7vec"k")` = 9

Cartesian equation

`(xvec"i" + yvec"j" + zvec"k")*(vec"i" + 10vec"j" + 7vec"k")` = 9

x + 10y + 7z – 9 = 0

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Different Forms of Equation of a Plane
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Applications of Vector Algebra - Exercise 6.7 [पृष्ठ २६३]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 6 Applications of Vector Algebra
Exercise 6.7 | Q 4 | पृष्ठ २६३

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