Advertisements
Advertisements
प्रश्न
Find the mean proportional to (x – y) and (x3 – x2y).
Advertisements
उत्तर
Let the mean proportional to (x – y) and (x3 – x2y) be n.
`=>` (x – y), n, (x3 – x2y) are in continued proportional
`=>` (x – y) : n = n : (x3 – x2y)
`=>` n2 = x2(x – y)(x – y)
`=>` n2 = x2(x – y)2
`=>` n = x(x – y)
संबंधित प्रश्न
Find the mean proportion of the following :
`28/3` and `175/27`
If y is the mean proportional between x and y; show that y(x+z) is the mean p roporti ona I between x2+ y2 and y2+ z2
Find the value of x in each of the following proportions:
55 : 11 : : x : 6
If a, b, c and d are in proportion, prove that: (a4 + c4) : (b4 + d4) = a2 c2 : b2 d2.
If q is the mean proportional between p and r, prove that: p3 – 3q2 + r2 = `q^4(1/p^2 - 3/q^2 + 1/r^2)`
`square` : 24 : : 3 : 8
Find whether 12, 24, 18, 36 are in order that can be expressed as two ratios that are in proportion
The shadow of a 3 m long stick is 4 m long. At the same time of the day, if the shadow of a flagstaff is 24 m long, how tall is the flagstaff?
Bachhu Manjhi earns Rs. 24000 in 8 months. At this rate, in how many months does he earn Rs. 42000?
If x, y and z are in continued proportion, Prove that:
`x/(y^2.z^2) + y/(z^2.x^2) + z/(x^2.y^2) = 1/x^3 + 1/y^3 + 1/z^3`
