Advertisements
Advertisements
प्रश्न
Find the mean proportional to (x – y) and (x3 – x2y).
Advertisements
उत्तर
Let the mean proportional to (x – y) and (x3 – x2y) be n.
`=>` (x – y), n, (x3 – x2y) are in continued proportional
`=>` (x – y) : n = n : (x3 – x2y)
`=>` n2 = x2(x – y)(x – y)
`=>` n2 = x2(x – y)2
`=>` n = x(x – y)
संबंधित प्रश्न
If a/b = c/d prove that each of the given ratio is equal to `(13a - 8c)/(13b - 8d)`
Find the value of the unknown in the following proportion :
3 : 4 : : p : 12
Find the smallest number that must be subtracted from each of the numbers 20, 29, 84 and 129 so that they are in proportion.
Find two numbers whose mean proportional is 18 and the third proportional is 486.
What number must be added to each of the numbers 6, 15, 20 and 43 to make them proportional?
Find the value of x in the following proportions : x : 50 :: 3 : 2
Find the mean proportion of: 8.1 and 2.5
If a, b, c and d are in proportion, prove that: `(a^2 + ab + b^2)/(a^2 - ab + b^2) = (c^2 + cd + d^2)/(c^2 - cd + d^2)`
If a, b, c are in continued proportion, prove that: `(a + b)/(b + c) = (a^2(b - c))/(b^2(a - b)`.
A student said that the ratios `3/4` and `9/16` were proportional. What error did the student make?
