Advertisements
Advertisements
प्रश्न
What number must be added to each of the numbers 5, 11, 19 and 37 so that they are in proportion?
Advertisements
उत्तर
Let x be added to 5, 11, 19 and 37 to make them in proportion.
5 + x : 11 + x : : 19 + x : 37 + x
⇒ (5 + x) (37 + x) = (11 + x) (19 + x)
⇒ 185 + 5x + 37x + x2 = 209 + 11x + 19x + x2
⇒ 185 + 42x + x2 = 209 + 30x + x2
⇒ 42x - 30x + x2 - x2 = 209 - 185
⇒ 12x = 24
⇒ x = 2
∴ Least number to be added = 2.
APPEARS IN
संबंधित प्रश्न
Using the properties of proportion, solve for x, given `(x^4 + 1)/(2x^2) = 17/8`.
If a, b, c are in continued proportion, show that: `(a^2 + b^2)/(b(a + c)) = (b(a + c))/(b^2 + c^2)`.
If `a/b = c/d`, show that: `(a^3c + ac^3)/(b^3d + bd^3) = (a + c)^4/(b + d)^4`.
Find the value of the unknown in the following proportion :
5 : 12 :: 15 : x
Find two nurnbers whose mean proportional is 12 and the third proportional is 324.
Write (T) for true and (F) for false in case of the following:
81 kg : 45 kg : : 18 men : 10 men
The weight of 65 books is 13 kg.
(i) What is the weight of 80 such books?
(ii) How many such books weigh 6.4 kg?
40 men can finish a piece of work in 26 days. How many men will be needed to finish it in 16 days?
In an army camp, there were provisions for 550 men for 28 days. But, 700 men attended the camp. How long did the provisions last?
Determine if the following ratios form a proportion. Also, write the middle terms and extreme terms where the ratios form a proportion.
200 mL : 2.5 litre and ₹ 4 : ₹ 50
