हिंदी

Find the joint equation of the line passing through the origin and having inclinations 60° and 120°.

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प्रश्न

Find the joint equation of the line passing through the origin and having inclinations 60° and 120°.

योग
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उत्तर

Slope of the line having inclination θ is tan θ.

Inclinations of the given lines are 60° and 120°

∴ their slopes are m1 = tan 60° = `sqrt3` and

m2 = tan 120° = tan (180° - 60°)

= - tan 60° = - `sqrt 3`.

Since the lines pass through the origin, their equations are

y = `sqrt3"x"` and y = `- sqrt3"x"`

i.e. `sqrt3"x - y" = 0` and `sqrt3"x + y" = 0`

∴ the joint equation of these lines is

`(sqrt3"x - y")(sqrt3"x + y") = 0`

∴ 3x2 - y2 = 0

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अध्याय 4: Pair of Straight Lines - Miscellaneous Exercise 4 [पृष्ठ १३०]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 4 Pair of Straight Lines
Miscellaneous Exercise 4 | Q 1.04 | पृष्ठ १३०

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