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Find the separate equation of the line represented by the following equation: 2x2 + 2xy - y2 = 0

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प्रश्न

Find the separate equation of the line represented by the following equation:

2x2 + 2xy - y2 = 0

योग
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उत्तर

2x2 + 2xy - y2 = 0

The auxiliary equation is - m2 + 2m + 2 = 0

∴ m2 - 2m - 2 = 0

∴ m = `(2 +- sqrt((-2)^2 - 4(1)(-2)))/(2xx1)`

`= (2 +- sqrt(4 + 8))/2`

`= (2+- 2sqrt3)/2`

`= 1 +- sqrt3`

∴ m1 = 1 + `sqrt3` and m2 = 1 - `sqrt3` are the slopes of the lines.

∴ their separate equations are

y = m1x  and y = m2x

i.e. y = `(1 + sqrt3)"x"` and  y = `(1 - sqrt3)"x"`

i.e. `(sqrt3 + 1)"x" - "y" = 0`  and  `(sqrt3 - 1)"x" + "y" = 0`

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अध्याय 4: Pair of Straight Lines - Miscellaneous Exercise 4 [पृष्ठ १३१]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 4 Pair of Straight Lines
Miscellaneous Exercise 4 | Q 3.4 | पृष्ठ १३१

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