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Show that the following equation represents a pair of line. Find the acute angle between them:2x2 + xy - y2 + x + 4y - 3 = 0

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प्रश्न

Show that the following equation represents a pair of line. Find the acute angle between them:

2x2 + xy - y2 + x + 4y - 3 = 0

योग
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उत्तर

Comparing this equation with

ax2 + 2hxy + by2 + 2gx + 2fy + c = 0, we get,

a = 2, h = `1/2`, b = - 1, g = `1/2`, f = 2 and c = -3

Now, abc + 2fgh - af2 - bg2 - ch2 = 0

`=2(-1)(-3)+2(2)(1/2)(1/2)-2(2)^2-(-1)(1/2)^2-(-3)(1/2)^2`

`=6+1-8+1/4+3/4`

`=7-8+1`

`=8-8=0`

And, `h^2-ab=(1/2)^2-(2)(-1)`

`=1/4+2=9/4>0`

∴ the given equation represents a pair of lines.

Let θ be the acute angle between the lines.

∴ tan θ = `|(2sqrt("h"^2 - "ab"))/("a + b")|`

`= |(2sqrt((9/4)))/(2 - 1)|`

`= |2 xx3/2| = 3`

∴ tan θ = tan 3

∴ θ = tan-1 (3)

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अध्याय 4: Pair of Straight Lines - Miscellaneous Exercise 4 [पृष्ठ १३२]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 4 Pair of Straight Lines
Miscellaneous Exercise 4 | Q 13.2 | पृष्ठ १३२

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