हिंदी

Find the joint equation of the pair of lines through the origin and making an equilateral triangle with the line x = 3.

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प्रश्न

Find the joint equation of the pair of lines through the origin and making an equilateral triangle with the line x = 3.

योग
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उत्तर


Let OA and OB be the lines through the origin making an angle of 60° with the line x = 3.

∴ OA and OB make an angle of 30° and 150° with the positive direction of X-axis.

∴ Slope of OA = tan 30° = `1/sqrt3`

∴ Equation of the line OA is y = `1/sqrt3x`

∴ `sqrt3y` = x

∴ `x - sqrt3"y" = 0`

Slope of OB = tan 150°

= tan (180° – 30°)

= – tan 30°

= `- 1/sqrt3`

∴ Equation of the line OB is y = `-1/sqrt3x`

∴ `sqrt3y` = – x

∴ x + `sqrt3y` = 0

∴ Required combined equation of the lines is

`(x - sqrt3y)(x + sqrt3y)` = 0

i.e. x2 – 3y2 = 0

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अध्याय 4: Pair of Straight Lines - Miscellaneous Exercise 4 [पृष्ठ १३१]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 4 Pair of Straight Lines
Miscellaneous Exercise 4 | Q 7 | पृष्ठ १३१

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