हिंदी

Find the derivative of x2 cosx.

Advertisements
Advertisements

प्रश्न

Find the derivative of x2 cosx.

योग
Advertisements

उत्तर

Let y = x2 cosx

Differentiating both sides with respect to x, we

`(dy)/(dx) = d/(dx)(x^2 cos x)`

= `x^2 d/(dx) (cos x) + cos x d/(dx) (x^2)`

= `x^2(- sinx) + cosx (2x)`

= `2x cosx - x^2 sinx`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 13: Limits and Derivatives - Solved Examples [पृष्ठ २३२]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
अध्याय 13 Limits and Derivatives
Solved Examples | Q 13 | पृष्ठ २३२

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the derivative of x at x = 1.


Find the derivative of x–3 (5 + 3x).


Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):

`(1 + 1/x)/(1- 1/x)`


Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):

`(ax + b)/(px^2 + qx + r)`


Find the derivative of f (x) = 99x at x = 100 


Find the derivative of f (x) = cos x at x = 0


Find the derivative of the following function at the indicated point: 

 sin x at x =\[\frac{\pi}{2}\]

 


\[\frac{1}{\sqrt{x}}\]


\[\frac{x^2 - 1}{x}\]


\[\frac{1}{\sqrt{3 - x}}\]


Differentiate  of the following from first principle:

 eax + b


x ex


Differentiate each of the following from first principle:

\[\sqrt{\sin 2x}\] 


Differentiate each of the following from first principle:

\[\sqrt{\sin (3x + 1)}\]


Differentiate each  of the following from first principle:

\[e^\sqrt{2x}\]


\[\cos \sqrt{x}\]


\[\tan \sqrt{x}\] 


(2x2 + 1) (3x + 2) 


\[\frac{2 x^2 + 3x + 4}{x}\] 


\[\frac{1}{\sin x} + 2^{x + 3} + \frac{4}{\log_x 3}\] 


If for f (x) = λ x2 + μ x + 12, f' (4) = 15 and f' (2) = 11, then find λ and μ. 


logx2 x


x5 (3 − 6x−9


Differentiate each of the following functions by the product rule and the other method and verify that answer from both the methods is the same.

(3 sec x − 4 cosec x) (−2 sin x + 5 cos x)


\[\frac{a x^2 + bx + c}{p x^2 + qx + r}\] 


\[\frac{2^x \cot x}{\sqrt{x}}\] 


\[\frac{\sin x - x \cos x}{x \sin x + \cos x}\]


\[\frac{a + \sin x}{1 + a \sin x}\] 


\[\frac{1 + 3^x}{1 - 3^x}\]


\[\frac{p x^2 + qx + r}{ax + b}\]


\[\frac{x^5 - \cos x}{\sin x}\] 


\[\frac{x + \cos x}{\tan x}\] 


If |x| < 1 and y = 1 + x + x2 + x3 + ..., then write the value of \[\frac{dy}{dx}\] 


Mark the correct alternative in  of the following:

If\[f\left( x \right) = 1 - x + x^2 - x^3 + . . . - x^{99} + x^{100}\]then \[f'\left( 1 \right)\] 


Mark the correct alternative in of the following:
If \[f\left( x \right) = x^{100} + x^{99} + . . . + x + 1\]  then \[f'\left( 1 \right)\] is equal to 


Find the derivative of f(x) = tan(ax + b), by first principle.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×