हिंदी

Find the derivative of x at x = 1.

Advertisements
Advertisements

प्रश्न

Find the derivative of x at x = 1.

योग
Advertisements

उत्तर

Let f(x) = x Accordingly,

`f'(1) = lim_(h → 0)(f(1 + h) - f(1))/h`

= ` lim_(h → 0)((1 + h)- 1)/h`

= `lim_(h->0)h/h`

= `lim_(h->0)(1)`

= 1

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Limits and Derivatives - EXERCISE 12.2 [पृष्ठ २४८]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 11
अध्याय 12 Limits and Derivatives
EXERCISE 12.2 | Q 2. | पृष्ठ २४८

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the derivative of x–3 (5 + 3x).


Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):

(ax + b)n (cx + d)m


Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):

sin (x + a)


Find the derivative of f (x) = 3x at x = 2 


Find the derivative of f (x) = 99x at x = 100 


Find the derivative of (x) = tan x at x = 0 


Find the derivative of the following function at the indicated point: 

 sin 2x at x =\[\frac{\pi}{2}\]


(x + 2)3


 (x2 + 1) (x − 5)


Differentiate each of the following from first principle:

ex


Differentiate  of the following from first principle: 

− x


Differentiate  of the following from first principle:

\[\cos\left( x - \frac{\pi}{8} \right)\]


Differentiate  of the following from first principle:

 x sin x


Differentiate each of the following from first principle: 

\[\frac{\cos x}{x}\]


Differentiate each of the following from first principle:

 x2 sin x


Differentiate each of the following from first principle:

x2 e


Differentiate each of the following from first principle: 

\[e^{x^2 + 1}\]


Differentiate each of the following from first principle:

\[e^\sqrt{ax + b}\]


\[\cos \sqrt{x}\]


 log3 x + 3 loge x + 2 tan x


\[\left( \sqrt{x} + \frac{1}{\sqrt{x}} \right)^3\] 


\[\frac{2 x^2 + 3x + 4}{x}\] 


cos (x + a)


\[\text{ If } y = \left( \sin\frac{x}{2} + \cos\frac{x}{2} \right)^2 , \text{ find } \frac{dy}{dx} at x = \frac{\pi}{6} .\]


\[If y = \sqrt{\frac{x}{a}} + \sqrt{\frac{a}{x}}, \text{ prove that } 2xy\frac{dy}{dx} = \left( \frac{x}{a} - \frac{a}{x} \right)\]  


\[\text{ If } y = \frac{2 x^9}{3} - \frac{5}{7} x^7 + 6 x^3 - x, \text{ find } \frac{dy}{dx} at x = 1 .\] 


logx2 x


x4 (5 sin x − 3 cos x)


x5 (3 − 6x−9


Differentiate each of the following functions by the product rule and the other method and verify that answer from both the methods is the same.

(x + 2) (x + 3)

 


(ax + b)n (cx d)


\[\frac{a + \sin x}{1 + a \sin x}\] 


\[\frac{1}{a x^2 + bx + c}\] 


Write the value of \[\lim_{x \to c} \frac{f(x) - f(c)}{x - c}\] 


If \[\frac{\pi}{2}\] then find \[\frac{d}{dx}\left( \sqrt{\frac{1 + \cos 2x}{2}} \right)\]


Write the value of \[\frac{d}{dx}\left( \log \left| x \right| \right)\]


If |x| < 1 and y = 1 + x + x2 + x3 + ..., then write the value of \[\frac{dy}{dx}\] 


Mark the correct alternative in of the following:

If \[y = \sqrt{x} + \frac{1}{\sqrt{x}}\] then \[\frac{dy}{dx}\] at x = 1 is


(ax2 + cot x)(p + q cos x)


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×