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Find the Cartesian equation of the line which passes through the point (−2, 4, −5) and parallel to the line given by x+33=y-45=z+86. - Mathematics

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प्रश्न

Find the Cartesian equation of the line which passes through the point (−2, 4, −5) and parallel to the line given by `(x+3)/3 = (y-4)/5 = (z+8)/6`.

योग
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उत्तर

The required line is parallel to the line `(x + 3)/3 = (y - 4)/5 = (z + 8)/6`.

∴ The direction ratios of the required line are 3, 5, and 6, and they pass through the points (−2, 4, −5).

∴ Equation of the required line

`(x - (-2))/3 = (y - 4)/5 = (z - (-5))/6`

or `(x + 2)/3 = (y - 4)/5 = (z + 5)/6`

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Three Dimensional Geometry - Exercise 11.1 [पृष्ठ ४७७]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 11 Three Dimensional Geometry
Exercise 11.1 | Q 6 | पृष्ठ ४७७

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