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Find the Value of λ So that the Following Lines Are Perpendicular to Each Other. X − 5 5 λ + 2 = 2 − Y 5 = 1 − Z − 1 , X 1 = 2 Y + 1 4 λ = 1 − Z − 3 - Mathematics

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प्रश्न

Find the value of λ so that the following lines are perpendicular to each other. \[\frac{x - 5}{5\lambda + 2} = \frac{2 - y}{5} = \frac{1 - z}{- 1}, \frac{x}{1} = \frac{2y + 1}{4\lambda} = \frac{1 - z}{- 3}\]

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उत्तर

The equations of the given line \[\frac{x - 5}{5\lambda + 2} = \frac{2 - y}{5} = \frac{1 - z}{- 1} \text{    and    } \frac{x}{1} = \frac{2y + 1}{4\lambda} = \frac{1 - z}{- 3}\]s   

can be re-written as

\[\frac{x - 5}{5\lambda + 2} = \frac{y - 2}{- 5} = \frac{z - 1}{1} \text{            and                     } \frac{x}{1} = \frac{y + \frac{1}{2}}{2\lambda} = \frac{z - 1}{3}\] Since the given lines are perpendicular to each other,

we have 

\[\left( 5\lambda + 2 \right)1 - 5\left( 2\lambda \right) + 1\left( 3 \right) = 0\]

\[ \Rightarrow 5\lambda = 5\]

\[ \Rightarrow \lambda = 1\]

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अध्याय 28: Straight Line in Space - Exercise 28.2 [पृष्ठ १७]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 28 Straight Line in Space
Exercise 28.2 | Q 23 | पृष्ठ १७

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