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The Cartesian Equations of a Line Are X = Ay + B, Z = Cy + D. Find Its Direction Ratios and Reduce It to Vector Form.

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प्रश्न

The cartesian equations of a line are x = ay + bz = cy + d. Find its direction ratios and reduce it to vector form. 

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उत्तर

The cartesian equation of the given line is  \[x = ay + b, z = cy + d\] 

It can be re-written as 

\[\frac{x - b}{a} = \frac{y - 0}{1} = \frac{z - d}{c}\] 

Thus, the given line passes through the point   (b,0,d)   and its direction ratios are proportional to a, 1, c. It is also parallel to the vector  \[\vec{b} = a \hat{i}  + \hat{j}  + c \hat{ k} \] 

We know that the vector equation of a line passing through a point with position vector ` vec a` and parallel to the vector `vec b` is  \[\vec{r} = \vec{a} + \lambda \vec{b}\]

Vector equation of the required line is 

\[\vec{r} = \left( b \hat{i} + 0 \hat{j} + d \hat{k} \right) + \lambda \left( a \hat{i} + \hat{j} + c \hat{k} \right)\]

\[\text{ Here }, \lambda \text{ is a parameter } . \]

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अध्याय 27: Straight Line in Space - Exercise 28.1 [पृष्ठ १०]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 27 Straight Line in Space
Exercise 28.1 | Q 12 | पृष्ठ १०

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