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Find the Real Value of a for Which 3 I 3 − 2 a I 2 + ( 1 − a ) I + 5 is Real.

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प्रश्न

Find the real value of a for which \[3 i^3 - 2a i^2 + (1 - a)i + 5\] is real.

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उत्तर

\[3 i^3 - 2a i^2 + (1 - a)i + 5\]

\[ = - 3i + 2a + (1 - a)i + 5\]

\[ = (2a + 5) + i(1 - a - 3)\]

\[ = (2a + 5) + i( - 2 - a)\]

Since, 

\[3 i^3 - 2a i^2 + (1 - a)i + 5\] is real.

\[\therefore Im\left[ 3 i^3 - 2a i^2 + (1 - a)i + 5 \right] = 0\]

\[ \Rightarrow - 2 - a = 0\]

\[ \Rightarrow a = - 2\]

Hence, the real value of for which 

\[3 i^3 - 2a i^2 + (1 - a)i + 5\] is real is −2.
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अध्याय 13: Complex Numbers - Exercise 13.5 [पृष्ठ ६३]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 13 Complex Numbers
Exercise 13.5 | Q 22 | पृष्ठ ६३

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