Advertisements
Advertisements
प्रश्न
Find, giving a reason, the unknown marked angles, in a triangle drawn below:

Advertisements
उत्तर
We know that,
Exterior angle of a triangle is always equal to the sum of its two interior opposite angles (property)
110° = 2x + 3x
5x – 110°
x = `110^circ/5`
x = 22°
∴ 2x = 2 x 22 = 44°
3x = 3 x 22 = 66°
APPEARS IN
संबंधित प्रश्न
Is the following statement true and false :
Sum of the three angles of a triangle is 180 .
In the given figure, AM ⊥ BC and AN is the bisector of ∠A. If ∠B = 65° and ∠C = 33°, find ∠MAN.

Side BC of a triangle ABC has been produced to a point D such that ∠ACD = 120°. If ∠B = \[\frac{1}{2}\]∠A is equal to
State, if the triangle is possible with the following angles :
20°, 70°, and 90°
Find the unknown marked angles in the given figure:

The angle of a vertex of an isosceles triangle is 100°. Find its base angles.
Can a triangle together have the following angles?
85°, 95° and 22°
Classify the following triangle according to angle:

D is any point on side AC of a ∆ABC with AB = AC. Show that CD < BD.
In the following figure, AD is the bisector of ∠BAC. Prove that AB > BD.

