Advertisements
Advertisements
प्रश्न
Find, giving a reason, the unknown marked angles, in a triangle drawn below:
Advertisements
उत्तर
We know that,
Exterior angle of a triangle is always equal to the sum of its two interior opposite angles (property)
110° = 2x + 3x
5x – 110°
x = `110^circ/5`
x = 22°
∴ 2x = 2 x 22 = 44°
3x = 3 x 22 = 66°
APPEARS IN
संबंधित प्रश्न
Can a triangle have two obtuse angles? Justify your answer in case.
Define a triangle.
In ΔABC, if bisectors of ∠ABC and ∠ACB intersect at O at angle of 120°, then find the measure of ∠A.
An exterior angle of a triangle is 108° and its interior opposite angles are in the ratio 4 : 5. The angles of the triangle are
Calculate the unknown marked angles of the following figure :
Find the unknown marked angles in the given figure:
In the given figure, show that: ∠a = ∠b + ∠c
(i) If ∠b = 60° and ∠c = 50° ; find ∠a.
(ii) If ∠a = 100° and ∠b = 55° : find ∠c.
(iii) If ∠a = 108° and ∠c = 48° ; find ∠b.
In the following, find the marked unknown angle:
Classify the following triangle according to angle:
The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
12 cm, 12 cm, 16 cm
