Advertisements
Advertisements
प्रश्न
Find, giving a reason, the unknown marked angles, in a triangle drawn below:
Advertisements
उत्तर
We know that,
Exterior angle of a triangle is always equal to the sum of its two interior opposite angles (property)
110° = 2x + 3x
5x – 110°
x = `110^circ/5`
x = 22°
∴ 2x = 2 x 22 = 44°
3x = 3 x 22 = 66°
APPEARS IN
संबंधित प्रश्न
If the angles of a triangle are in the ratio 1: 2 : 3, determine three angles.
If one angle of a triangle is equal to the sum of the other two, show that the triangle is a
right triangle.
If each angle of a triangle is less than the sum of the other two, show that the triangle is acute angled.
In the given figure, if AB || CD, EF || BC, ∠BAC = 65° and ∠DHF = 35°, find ∠AGH.
In the given figure, side BC of ΔABC is produced to point D such that bisectors of ∠ABC and ∠ACD meet at a point E. If ∠BAC = 68°, find ∠BEC.
State, if the triangle is possible with the following angles :
40°, 130°, and 20°
Find the value of the angle in the given figure:
Calculate the angles of a triangle if they are in the ratio 4: 5: 6.
One angle of a triangle is 60°. The other two angles are in the ratio of 5: 7. Find the two angles.
What is the sum of the measures of the interior angles of any triangle, △ABC?
