Advertisements
Advertisements
प्रश्न
Find, giving a reason, the unknown marked angles, in a triangle drawn below:
Advertisements
उत्तर
We know that,
Exterior angle of a triangle is always equal to the sum of its two interior opposite angles (property)
110° = 2x + 3x
5x – 110°
x = `110^circ/5`
x = 22°
∴ 2x = 2 x 22 = 44°
3x = 3 x 22 = 66°
APPEARS IN
संबंधित प्रश्न
In a ΔABC, ∠ABC = ∠ACB and the bisectors of ∠ABC and ∠ACB intersect at O such that ∠BOC = 120°. Show that ∠A = ∠B = ∠C = 60°.
In the given figure, side BC of ΔABC is produced to point D such that bisectors of ∠ABC and ∠ACD meet at a point E. If ∠BAC = 68°, find ∠BEC.
In a triangle, an exterior angle at a vertex is 95° and its one of the interior opposite angle is 55°, then the measure of the other interior angle is
In ΔRST (See figure), what is the value of x?
Find the unknown marked angles in the given figure:
Find x, if the angles of a triangle is:
x°, 2x°, 2x°
The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
17 cm, 7 cm, 8 cm
The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
8.4 cm, 16.4 cm, 4.9 cm
In the following figure, AD is the bisector of ∠BAC. Prove that AB > BD.
Can we have two acute angles whose sum is an obtuse angle? Why or why not?
