Advertisements
Advertisements
प्रश्न
Calculate the unknown marked angles of the following figure :
Advertisements
उत्तर
We know that the sum of three angles of a triangle is 180°, therefore
In figure,
y + 80° + 20° = 180°
⇒ y + 100° = 180°
⇒ y = 180° − 100° = 80°
Hence y = 80°
APPEARS IN
संबंधित प्रश्न
Compute the value of x in the following figure:
Is the following statement true and false :
An exterior angle of a triangle is less than either of its interior opposite angles.
Is the following statement true and false :
An exterior angle of a triangle is greater than the opposite interior angles.
In a Δ ABC, AD bisects ∠A and ∠C > ∠B. Prove that ∠ADB > ∠ADC.
In Δ ABC, BD⊥ AC and CE ⊥ AB. If BD and CE intersect at O, prove that ∠BOC = 180° − A.
In the given figure, express a in terms of b.
In ∆ABC, C = 56° C = 56° ∠B = ∠C and ∠A = 100° ; find ∠B.
As shown in the figure, Avinash is standing near his house. He can choose from two roads to go to school. Which way is shorter? Explain why.
Draw a rough sketch of a triangle ABC. Mark a point P in its interior and a point Q in its exterior. Is point A in its exterior or in its interior?
Identify three triangles in the figure.
