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Find: 18th Term of the A.P. √ 2 , 3 √ 2 , 5 √ 2 ,

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प्रश्न

Find: 

18th term of the A.P.

\[\sqrt{2}, 3\sqrt{2}, 5\sqrt{2},\]

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उत्तर

\[\sqrt{2}, 3\sqrt{2}, 5\sqrt{2}\]......

We have:

\[a = \sqrt{2}\]

\[d = 3\sqrt{2} - \sqrt{2} = 2\sqrt{2}\]

\[a_{18} = a + \left( 18 - 1 \right)d \left[ a_n = a + \left( n - 1 \right)d \right] \]

\[ = a + 17d\]

\[ = \sqrt{2} + 17\left( 2\sqrt{2} \right)\]

\[ = \sqrt{2} + 34\sqrt{2}\]

\[ = 35 \sqrt{2}\]

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अध्याय 19: Arithmetic Progression - Exercise 19.2 [पृष्ठ ११]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 19 Arithmetic Progression
Exercise 19.2 | Q 1.2 | पृष्ठ ११

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