Advertisements
Advertisements
प्रश्न
Find:-
`16^(3/4)`
योग
Advertisements
उत्तर
We can write the given expression as follows
⇒ `16^(3/4) = (2^4)^(3/4)`
On simplifying
⇒ `16^(3/4) = 2^(4 xx 3/4)`
⇒ `16^(3/4) = 2^3`
∴ `16^(3/4) = 8`
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Number Systems - EXERCISE 1.5 [पृष्ठ २३]
APPEARS IN
संबंधित प्रश्न
Simplify the following
`((x^2y^2)/(a^2b^3))^n`
Prove that:
`(a^-1+b^-1)^-1=(ab)/(a+b)`
Solve the following equation for x:
`4^(2x)=1/32`
Prove that:
`9^(3/2)-3xx5^0-(1/81)^(-1/2)=15`
Show that:
`(x^(1/(a-b)))^(1/(a-c))(x^(1/(b-c)))^(1/(b-a))(x^(1/(c-a)))^(1/(c-b))=1`
If 102y = 25, then 10-y equals
If \[\frac{3^{5x} \times {81}^2 \times 6561}{3^{2x}} = 3^7\] then x =
If x= \[\frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} + \sqrt{2}}\] and y = \[\frac{\sqrt{3} + \sqrt{2}}{\sqrt{3} - \sqrt{2}}\] , then x2 + y +y2 =
The value of \[\sqrt{3 - 2\sqrt{2}}\] is
Simplify:
`11^(1/2)/11^(1/4)`
