Advertisements
Advertisements
प्रश्न
The value of \[\sqrt{3 - 2\sqrt{2}}\] is
विकल्प
\[\sqrt{2} - 1\]
\[\sqrt{2} + 1\]
\[\sqrt{3} - \sqrt{2}\]
\[\sqrt{3} + \sqrt{2}\]
Advertisements
उत्तर
Given that:`sqrt(3 -2sqrt2)` It can be written in the form `(a-b)^2 = a^2+b^2 -2ab` as
`sqrt(3 -2sqrt2) = sqrt(2+1-2 xx 1 xxsqrt2)`
` = sqrt((sqrt2 )^2 + (1)^2 - 2 xx 1 xx sqrt2)`
`= sqrt((sqrt2-1)^2)`
` = sqrt2 - 1.`
APPEARS IN
संबंधित प्रश्न
Find:-
`64^(1/2)`
If `1176=2^a3^b7^c,` find a, b and c.
`(2/3)^x (3/2)^(2x)=81/16 `then x =
The value of m for which \[\left[ \left\{ \left( \frac{1}{7^2} \right)^{- 2} \right\}^{- 1/3} \right]^{1/4} = 7^m ,\] is
If \[\frac{3^{2x - 8}}{225} = \frac{5^3}{5^x},\] then x =
If \[\sqrt{5^n} = 125\] then `5nsqrt64`=
If \[x + \sqrt{15} = 4,\] then \[x + \frac{1}{x}\] =
If x= \[\frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} + \sqrt{2}}\] and y = \[\frac{\sqrt{3} + \sqrt{2}}{\sqrt{3} - \sqrt{2}}\] , then x2 + y +y2 =
Simplify:
`7^(1/2) . 8^(1/2)`
Simplify:
`(3/5)^4 (8/5)^-12 (32/5)^6`
