Advertisements
Advertisements
प्रश्न
Prove that:
`(a^-1+b^-1)^-1=(ab)/(a+b)`
Advertisements
उत्तर
Consider the left hand side:
`(a^-1+b^-1)^-1`
`=1/(a^-1+b^-1)`
`=1/(1/a+1/b)`
`=1/((b+a)/(ab))`
`=(ab)/(a+b)`
Therefore left hand side is equal to the right hand side. Hence proved.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Simplify the following
`(a^(3n-9))^6/(a^(2n-4))`
Prove that:
`(x^a/x^b)^cxx(x^b/x^c)^axx(x^c/x^a)^b=1`
Solve the following equation for x:
`2^(3x-7)=256`
Solve the following equations for x:
`3^(2x+4)+1=2.3^(x+2)`
Simplify:
`(0.001)^(1/3)`
Simplify:
`(sqrt2/5)^8div(sqrt2/5)^13`
If ax = by = cz and b2 = ac, show that `y=(2zx)/(z+x)`
Solve the following equation:
`3^(x+1)=27xx3^4`
If x-2 = 64, then x1/3+x0 =
\[\frac{1}{\sqrt{9} - \sqrt{8}}\] is equal to
