Advertisements
Advertisements
प्रश्न
Factorise : a2 - 81 (b-c)2
योग
Advertisements
उत्तर
a2 - 81 (b-c)2
= ( a )2 - [ 9( b - c ) ]2
= [ a - ( 9b - 9c )][ a + ( 9b - 9c )] [ ∵ a2 - b2 = ( a + b )( a - b )]
= ( a - 9b + 9c )( a + 9b - 9c )
shaalaa.com
Method of Factorisation : Difference of Two Squares
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise : 50a3 - 2a
Factorise : 9(a - 2)2 - 16(a + 2)2
Factorise : a4 - 1
Factorise : 4x2 - 12ax - y2 - z2 - 2yz + 9a2
Factorise : x4 + x2 + 1
Factorise : (x2 + 4y2 - 9z2)2 - 16x2y2
Factorise the following by the difference of two squares:
441 - 81y2
Factorise the following by the difference of two squares:
625 - b2
Factorise the following by the difference of two squares:
a(a - 1) - b(b - 1)
Factorise the following:
4xy - x2 - 4y2 + z2
