Advertisements
Advertisements
प्रश्न
Factorise : a2 - 81 (b-c)2
बेरीज
Advertisements
उत्तर
a2 - 81 (b-c)2
= ( a )2 - [ 9( b - c ) ]2
= [ a - ( 9b - 9c )][ a + ( 9b - 9c )] [ ∵ a2 - b2 = ( a + b )( a - b )]
= ( a - 9b + 9c )( a + 9b - 9c )
shaalaa.com
Method of Factorisation : Difference of Two Squares
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Factorise : 25a2 - 9b2
Factorise : 25(2a - b)2 - 81b2
Factorise : 9a2 + 3a - 8b - 64b2
Factorise : (a2 + b2 - 4c2)2 - 4a2b2
Factorise : (x2 + 4y2 - 9z2)2 - 16x2y2
Factorise the following by the difference of two squares:
625 - b2
Factorise the following by the difference of two squares:
x2 + y2 - z2 - 2xy
Factorise the following:
25(x - y)2 - 49(c - d)2
Factorise the following:
(2a - b)2 -9(3c - d)2
Factorise the following:
4x2 - 12ax - y2 - z2 - 2yz + 9a2
