Advertisements
Advertisements
प्रश्न
Factorise : 25(2a - b)2 - 81b2
Advertisements
उत्तर
25(2a - b)2 - 81b2
= [ 5( 2a - b )]2 - (9b)2
= [ 5( 2a - b ) - 9b ][ 5( 2a - b ) + 9b ]
[ ∵ a2 - b2 = ( a + b )( a - b )]
= [ 10a - 5b - 9b ][ 10a - 5b + 9b ]
= [ 10a - 14b ][ 10a + 4b ]
= 2 x ( 5a - 7b ) x 2 x ( 5a + 2b )
= 4( 5a - 7b )( 5a + 2b )
APPEARS IN
संबंधित प्रश्न
Factorise : (a + b)3 - a - b
Factorise: 4a2 - (4b2 + 4bc + c2)
Factorise : a2 + b2 - c2 - d2 + 2ab - 2cd
Factorise the following by the difference of two squares:
16a4 - 81b4
Factorise the following:
b2 - 2bc + c2 - a2
Factorise the following:
a2 + b2 – c2 – d2 + 2ab – 2cd
Factorise the following:
4xy - x2 - 4y2 + z2
Factorise the following:
(x + y)3 - x - y
Express each of the following as the difference of two squares:
(x2 - 2x + 3) (x2 - 2x - 3)
Express each of the following as the difference of two squares:
(x2 + 2x - 3) (x2 - 2x + 3)
