Advertisements
Advertisements
प्रश्न
Factorise the following:
y4 + y2 + 1
बेरीज
Advertisements
उत्तर
y4 + y2 + 1
= y4 + 2y2 + 1 - y2
= (y2 + 1)2 - y2
= (y2 + 1 + y)(y2 + 1 - y).
shaalaa.com
Method of Factorisation : Difference of Two Squares
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Factorise : a2 - 81 (b-c)2
Factorise:
9(a − 2)2 − 16(a + 2)2
Factorise: 4a2 - (4b2 + 4bc + c2)
Factorise : 4a2 - 12a + 9 - 49b2
Factorise : x4 + x2 + 1
Factorise : `4x^2 + 1/(4x)^2 + 1`
Factorise the following:
b2 - 2bc + c2 - a2
Factorise the following:
a2 + b2 – c2 – d2 + 2ab – 2cd
Factorise the following:
4x2 - 12ax - y2 - z2 - 2yz + 9a2
Express each of the following as the difference of two squares:
(x2 - 2x + 3) (x2 - 2x - 3)
