Advertisements
Advertisements
प्रश्न
Factorise : a2 - (2a + 3b)2
योग
Advertisements
उत्तर
a2 - (2a + 3b)2
= a2 - ( 2a + 3b )2
= ( a - 2a - 3b )( a + 2a + 3b ) [ ∵ a2 - b2 = ( a + b )(a - b)]
= ( - a - 3b )( 3a + 3b )
= - 3( a + 3b )( a + b )
shaalaa.com
Method of Factorisation : Difference of Two Squares
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise : a2 - 81 (b-c)2
Factorise : 4xy - x2 - 4y2 + z2
Factorise : (a2 + b2 - 4c2)2 - 4a2b2
Factorise : (a + b) 2 - a2 + b2
Factorise : a2 - b2 - (a + b) 2
Factorise the following by the difference of two squares:
x2 - 16
Factorise the following by the difference of two squares:
(x - 2y)2 -z2
Factorise the following:
(x2 + y2 – z2)2 – 4x2y2
Express each of the following as the difference of two squares:
(x2 - 2x + 3) (x2 - 2x - 3)
Express each of the following as the difference of two squares:
(x2 + 2x - 3) (x2 - 2x + 3)
