हिंदी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान कक्षा ११

Explain Why Two Bodies at Different Temperatures T1 And T2 If Brought in Thermal Contact Do Not Necessarily Settle to the Mean Temperature (T1 + T2)/2.

Advertisements
Advertisements

प्रश्न

Explain why Two bodies at different temperatures T1 and T2, if brought in thermal contact, do not necessarily settle to the mean temperature (T1 + T2)/2.

Advertisements

उत्तर १

When two bodies at different temperatures T1 and T2 are brought in thermal contact, heat flows from the body at the higher temperature to the body at the lower temperature till equilibrium is achieved, i.e., the temperatures of both the bodies become equal. The equilibrium temperature is equal to the mean temperature (T1 + T2)/2 only when the thermal capacities of both the bodies are equal.

shaalaa.com

उत्तर २

In thermal contact, heat flows from the body at higher temperature to the body at lower temperature till temperatures become equal. The final temperature can be the mean temperature (T1+ T2)/2 only when thermal capacities of the two bodies are equal.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?

संबंधित प्रश्न

Should the internal energy of a system necessarily increase if its temperature is increased?


When we rub our hands they become warm. Have we supplied heat to the hands?


The final volume of a system is equal to the initial volume in a certain process. Is the work done by the system necessarily zero? Is it necessarily nonzero?


Consider the process on a system shown in figure. During the process, the work done by the system ______________ .


An ideal gas goes from the state i to the state f as shown in figure. The work done by the gas during the process ______________ .


Consider two processes on a system as shown in figure.

The volumes in the initial states are the same in the two processes and the volumes in the final states are also the same. Let ∆W1 and ∆W2 be the work done by the system in the processes A and B respectively.


Figure shows a cylindrical tube of volume V with adiabatic walls containing an ideal gas. The internal energy of this ideal gas is given by 1.5 nRT. The tube is divided into two equal parts by a fixed diathermic wall. Initially, the pressure and the temperature are p1, T1 on the left and p2, T2 on the right. The system is left for sufficient time so that the temperature becomes equal on the two sides. (a) How much work has been done by the gas on the left part? (b) Find the final pressures on the two sides. (c) Find the final equilibrium temperature. (d) How much heat has flown from the gas on the right to the gas on the left?


What is the energy associated with the random, disordered motion of the molecules of a system called as?


A system releases 100 kJ of heat while 80 kJ of work is done on the system. Calculate the change in internal energy.


Explain given cases related to energy transfer between the system and surrounding –

  1. energy transferred (Q) > 0
  2. energy transferred (Q) < 0
  3. energy transferred (Q) = 0 

One gram of water (1 cm3) becomes 1671 cm3 of steam at a pressure of 1 atm. The latent heat of vaporization at this pressure is 2256 J/g. Calculate the external work and the increase in internal energy. 


derive the relation between the change in internal energy (∆U), work is done (W), and heat (Q). 


An ideal gas is compressed at a constant temperature. Its internal energy will ____________.


Two cylinders A and B of equal capacity are connected to each other via a stopcock. A contains a gas at standard temperature and pressure. B is completely evacuated. The entire system is thermally insulated. The stopcock is suddenly opened. Answer the following:

What is the change in internal energy of the gas?


Two cylinders A and B of equal capacity are connected to each other via a stopcock. A contains a gas at standard temperature and pressure. B is completely evacuated. The entire system is thermally insulated. The stopcock is suddenly opened. Answer the following:

What is the change in the temperature of the gas?


n mole of a perfect gas undergoes a cyclic process ABCA (see figure) consisting of the following processes:

A `→` B: Isothermal expansion at temperature T so that the volume is doubled from V1 to V2 = 2V1 and pressure changes from P1 to P2.

B `→` C: Isobaric compression at pressure P2 to initial volume V1.

C `→` A: Isochoric change leading to change of pressure from P2 to P1.

Total workdone in the complete cycle ABCA is ______.


Explain the change in internal energy of a thermodynamic system (the gas) by heating it.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×